[Graduate Thermodynamics/Probability] HW Help HomeworkHelp

Question:

1. I make jewelry as a hobby. I am planning to produce a set of earrings and a necklace. I have placed 6 identical red beads and 4 different flower shaped beads out on a surface that the beads can stick to slightly (similar to a post-it-note type of glue). Before I can choose the rest of the beads I get a phone call and I am called away to care for a sick relative for a few days and leave the house in hurry leaving the bead project on the dining room table. My husband is left to care for our two grade-school aged children and ignores the bead project. a. My daughter loves to play with the beads. She invents a game making arrangements of the beads. Calculate how many different arrangements she can make with the beads in my absence. Assume she always uses all 10 beads and is putting these in lines of beads like she is making necklaces. b. My husband takes the beads away from her to get her to do her homework and places the beads on top of the refrigerator still stuck down to the glue-paper in the last arrangement she made. What is the probability that when I get home to find the beads these are in the prefect arrangement of 3 reds on each side of the 4 flower shaped beads.

Attempt at asnwer: A. This seems straight forward: 10!/6! = 5040 possibilities

B. This is tougher. I think the answer is 6/10x5/9x4/8x4/7x3/6x2/5x1/4 (the chance of choosing three reds and then 4 flower beads). The last three reds must be chosen. The final answer is P=.00476

In my opinion, the fact that the flower beads are distinguishable does not matter for Part B (but my teacher in an email told me it was). What is the opinion, or where am I wrong?

Submitted March 16, 2016 at 10:43PM by DH85 http://ift.tt/1Ug7e0w HomeworkHelp